(x-3)^(2)-2(x+1)=5x+37

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Solution for (x-3)^(2)-2(x+1)=5x+37 equation: 



(x-3)^(2)-2(x+1)=5x+37

We move all terms to the left:

(x-3)^(2)-2(x+1)-(5x+37)=0

We multiply parentheses

(x-3)^2-2x-(5x+37)-2=0

We get rid of parentheses

(x-3)^2-2x-5x-37-2=0

We add all the numbers together, and all the variables

-7x+(x-3)^2-39=0

We move all terms containing x to the left, all other terms to the right

-7x+(x-3)^2=39

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